C++关于“烫”

Employee::Employee()

{

char name[10]="Tommy";

char streetname[10]="Yujiahu";

char city[10]="Wuhan";

int post[10]={4,3,0,0,7,4};

}

你在这个函数定义的 name，streetname等变量和 你类中定义的成员是不一样的哦，这个等你退出这个构造函数，这些变量就释放掉了，你类中的那些name等还是没设置，所以输出"烫"，程序给你改过了

#include<iostream>

using namespace std;

class Employee

{

public:

Employee();

void chage_name(char s[10]);

void display();

private:

char name[10];

char streetname[10];

char city[10];

char post[10];

};

Employee::Employee()

{

strcpy(name, "Tommy");

strcpy(streetname,"Yujiahu");

strcpy(city,"Wuhan");

strcpy(post, "430047");

}

void Employee::chage_name(char s[10])

{

int i;

for(i=0;i<10;i++)

name[i]=s[i];

}

void Employee::display()

{

int i;

cout<<"The name is"<<" ";

for(i=0;name[i]!="";i++)

{

cout<<name[i];

}

cout<<endl<<"The streetname is ";

for(i=0;streetname[i]!="";i++)

{

cout<<streetname[i];

}

cout<<endl<<"The city is ";

for(i=0;city[i]!="";i++)

{

cout<<city[i];

}

cout<<endl<<"The post is ";

for(i=0;post[i]!="";i++)

{

cout<<post[i];

}

cout<<endl;

}

void main()

{

char t[10];

cin>>t;

Employee Em;

Em.display();

Em.chage_name(t);

Em.display();

}

主要原因是你构造函数中变量是重新定义的，并没有初始化类成员。所以在display的时候，输出那么多烫，程序修改如下。你看看。

#include<iostream>

using namespace std;

class Employee

{

public:

Employee();

void chage_name(char s[10]);

void display();

private:

char *name;

char *streetname;

char *city;

int post;

};

Employee::Employee()

{

name="Tommy";

streetname="Yujiahu";

city="Wuhan";

post=430074;

}

void Employee::chage_name(char *s)

{

name=s;

}

void Employee::display()

{

int i;

cout<<"The name is"<<" ";

for(i=0;name[i]!="";i++)

{

cout<<name[i];

}

cout<<endl<<"The streetname is";

for(i=0;streetname[i]!="";i++)

{

cout<<streetname[i];

}

cout<<endl<<"The city is";

for(i=0;city[i]!="";i++)

{

cout<<city[i];

}

cout<<endl<<"The post is";

cout<<post;

}

void main()

{

char t[10];

cin>>t;

Employee Em;

Em.display();

Em.chage_name(t);

Em.display();

}

输出烫表示输出的是乱码了

Employee::Employee()

{

char name[10]="Tommy";

char streetname[10]="Yujiahu";

char city[10]="Wuhan";

int post[10]={4,3,0,0,7,4};

}

在你对Employee的构造函数中，并没有实现对类成员的初始化，而是重新定义了几个数组。

所以你在display操作中输出这些成员时，由于他们并没有被初始化，具有不确定的值，所以输出的是乱码

#include<iostream>

using namespace std;

class Employee

{

public:

Employee();

void chage_name(char s[10]);

void display();

private:

char name[10];

char streetname[10];

char city[10];

char post[10];

};

Employee::Employee()

{

strcpy(name, "Tommy");

strcpy(streetname, "Yujiahu");

strcpy(city, "Wuhan");

strcpy(post, "430074");

}

void Employee::chage_name(char s[10])

{

int i;

for(i=0;i<10;i++)

name[i]=s[i];

}

void Employee::display()

{

int i;

cout<<"The name is ";

for(i=0;name[i]!="";i++)

{

cout<<name[i];

}

cout<<endl<<"The streetname is ";

for(i=0;streetname[i]!="";i++)

{

cout<<streetname[i];

}

cout<<endl<<"The city is ";

for(i=0;city[i]!="";i++)

{

cout<<city[i];

}

cout<<endl<<"The post is ";

for(i=0;post[i]!="";i++)

{

cout<<post[i];

}

cout<<endl;

}

void main()

{

char t[10];

cin>>t;

Employee Em;

Em.display();

Em.chage_name(t);

Em.display();

system("pause");

}

因为内存的问题